b^2=249

Solution for b^2=249 equation:

b^2=249

We move all terms to the left:

b^2-(249)=0

a = 1; b = 0; c = -249;
Δ = b2-4ac
Δ = 02-4·1·(-249)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{249}}{2*1}=\frac{0-2\sqrt{249}}{2}
=-\frac{2\sqrt{249}}{2}
=-\sqrt{249}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{249}}{2*1}=\frac{0+2\sqrt{249}}{2}
=\frac{2\sqrt{249}}{2}
=\sqrt{249}
$